- : unit = () h : heuristic = - : unit = () APPLY CRITERIA (Marked dependency pairs) TRS termination of: [1] f(a,f(b,f(a,x))) -> f(a,f(b,f(b,f(a,x)))) [2] f(b,f(b,f(b,x))) -> f(b,f(b,x)) Sub problem: guided: DP termination of: END GUIDED APPLY CRITERIA (Graph splitting) Found 1 components: { --> } APPLY CRITERIA (Choosing graph) Trying to solve the following constraints: { f(a,f(b,f(a,x))) >= f(a,f(b,f(b,f(a,x)))) ; f(b,f(b,f(b,x))) >= f(b,f(b,x)) ; Marked_f(a,f(b,f(a,x))) >= Marked_f(a,f(b,f(b,f(a,x)))) ; } + Disjunctions:{ { Marked_f(a,f(b,f(a,x))) > Marked_f(a,f(b,f(b,f(a,x)))) ; } } === TIMER virtual : 10.000000 === Entering poly_solver Starting Sat solver initialization Calling Sat solver... === STOPING TIMER virtual === === TIMER real : 10.000000 === === STOPING TIMER real === Sat solver returned === STOPING TIMER real === === STOPING TIMER virtual === No solution found for these parameters. Entering rpo_solver === TIMER virtual : 25.000000 === Search parameters: AFS type: 2 ; time limit: 25.. === STOPING TIMER virtual === === TIMER virtual : 15.000000 === Entering poly_solver Starting Sat solver initialization Calling Sat solver... === STOPING TIMER virtual === === TIMER real : 15.000000 === === STOPING TIMER real === Sat solver returned === STOPING TIMER real === === STOPING TIMER virtual === No solution found for these parameters. === TIMER virtual : 50.000000 === trying sub matrices of size: 1 Matrix interpretation constraints generated. Search parameters: LINEAR MATRIX 3x3 (strict=1x1) ; time limit: 50.. Termination constraints generated. Starting Sat solver initialization Calling Sat solver... === STOPING TIMER virtual === === TIMER real : 50.000000 === === STOPING TIMER real === Sat solver returned Sat solver result read === STOPING TIMER real === === STOPING TIMER virtual === constraint: f(a,f(b,f(a,x))) >= f(a,f(b,f(b,f(a,x)))) constraint: f(b,f(b,f(b,x))) >= f(b,f(b,x)) constraint: Marked_f(a,f(b,f(a,x))) >= Marked_f(a,f(b,f(b,f(a,x)))) APPLY CRITERIA (Graph splitting) Found 0 components: SOLVED { TRS termination of: [1] f(a,f(b,f(a,x))) -> f(a,f(b,f(b,f(a,x)))) [2] f(b,f(b,f(b,x))) -> f(b,f(b,x)) , CRITERION: MDP [ { DP termination of: , CRITERION: SG [ { DP termination of: , CRITERION: ORD [ Solution found: Matrix polynomial interpretation (strict sub matrices size: 1x1) = [ f ] (X0,X1) = [ [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] [ 0 , 1 , 0 ] ]*X1 + [ [ 0 , 0 , 0 ] [ 0 , 1 , 0 ] [ 0 , 0 , 0 ] ]*X0 + [ [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] ]; [ b ] () = [ [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] ]; [ a ] () = [ [ 0 , 0 , 0 ] [ 1 , 0 , 0 ] [ 0 , 0 , 0 ] ]; [ Marked_f ] (X0,X1) = [ [ 0 , 0 , 1 ] [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] ]*X1 + [ [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] ]*X0 + [ [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] [ 0 , 0 , 0 ] ]; ]} ]} ]} Cime worked for 3.364369 seconds (real time) Cime Exit Status: 0